![]() Any number of duplicate files can then be identified when you see more than one of the same value in the CRC column. Ensure that the CRC column is visible and sort by it. Create this on your class: TaskCompletionSource tcs Then at every point that you want to wait for the user input, have this: this.tcs new TaskCompletionSource () await this.tcs.![]() You may need to repeat, doing Set2 first to find the alternate set of uniques. Those with the newer date are the unique files. Looking at this new location in File Explorer, add Date Created to the displayed columns. Choose the "Ignore Folder Structure" option from the Folder View dropdown to see a flattened view of all the jpg files together. Copy Set2 to the same location, choosing No, do not overwrite. Option 2 - If multiple duplicates of the same file are on the same hard-drive (but in different sub-folders), open a folder compare with the common parent folder on one side and leave the other side blank. Any files with the same CRC should be identical. Option 1 - Open a folder compare session, right-click on the column headers and ensure that the CRC column is showing. Im trying to find differences in the content of two folder structures using Windows Powershell. I use this script to find and remove duplicate files on linux system Script: rmdupe IgnorantGurus. This folder is our target for searching for duplicate files A window will pop-up to select duplicate files based on the hash value. This will find duplicates in current directory. Enter the full path to the destination folder. ![]() I don't know a simple way to script such a check with BC3, but you certainly can eye-ball it as follows: Open PowerShell (Windows Key + X + A) Navigate to the script location. BC3 doesn't currently allow you to automatically align files based on content, although that is in the wish list for a future version (as-is duplicate file finder functionality). ![]()
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